integral (4׳+6²+2×-1, JIKA f(1)=6 maka
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Jawab:
[tex]f=\int {4x^{3} +6x^{2} +2x-1} \, dx[/tex]
[tex]f=\frac{4}{3+1} x^{3+1} +\frac{6}{2+1} x^{2+1} +\frac{2}{1+1} x^{1+1} -x+c[/tex]
[tex]f=x^{4} +2x^{3} +x^{2} -x+c[/tex]
[tex]6=1^{4} +2(1)^3+1^2-1+c[/tex]
[tex]c=3[/tex]
[tex]f(x)=x^{4} +2x^{3} +x^{2} -x+3[/tex]
[answer.2.content]
